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Wednesday, September 19, 2007

Maths: Armstrong Numbers

Question: Divide the number 1301 into four three digit parts abc, def, ghi and jkl

so that

abc + def + ghi + jkl = 1301

and

abc = a^3 + b^3 + c^3
def = d^3 + e^3 + f^3
ghi = g^3 + h^3 + i^3
jkl = j^3 + k^3 + l^3




SOLUTION :

' This is related to “Armstrong Numbers”.

1301 = 153 + 370 + 371 + 407

These are the only 3 digit numbers that have this property.

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